Y 5x

If you're seeing this message, it means we're y 5x trouble loading external resources on our website. To log in and use all the features of Khan Academy, please enable JavaScript in your browser. Search for courses, skills, and videos. Solving systems with substitution.

Now in question number eight were asked, which of the following is the graph 2 of this equation, right? And the equation that they give us is Y 3 minus five X is equal to negative six. If you're ever trying to take an equation and turn 7 it into a graph you want to use Y intercept form, 8 which is Y equals MX plus B. Now, 14 if I'm trying to take that minus five X and move it from left 15 to, right, that means I need to add five X to both sides, 16 because that will allow the Xs to cancel on my left, 17 leaving me with just Y and then I'll have a plus five X, 18 which I can just write, um, is five X minus six. So our slope is 21 a positive number. It's a positive five. And our Y intercept is negative six.

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So they're parallel lines. I don't want to be repetitive, y 5x I really want you to internalize that's all it's saying. The second equation, let me rewrite it in slope y-intercept form.

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If you're seeing this message, it means we're having trouble loading external resources on our website. To log in and use all the features of Khan Academy, please enable JavaScript in your browser. Search for courses, skills, and videos. Solving systems of equations with substitution. The substitution method is a technique for solving a system of equations. This article reviews the technique with multiple examples and some practice problems for you to try on your own. What is the substitution method? The substitution method is a technique for solving systems of linear equations. Let's walk through a couple of examples.

Y 5x

If you're seeing this message, it means we're having trouble loading external resources on our website. To log in and use all the features of Khan Academy, please enable JavaScript in your browser. Search for courses, skills, and videos. Intro to slope-intercept form. About About this video Transcript.

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And instead of writing a y there, and I've said it multiple times already, we can write a negative 5x plus 8. Now, we have one equation with one unknown. This is our y-axis. So everywhere we see a y, we can substitute it with negative 5x plus 8. How would solves equations with squares? It's a positive five. They already have y explicitly solved for up here. So when we go to the second constraint here, every time we see a y, we say, well, the first constraint tells us that y must be equal to negative 5x plus 8. How would you solve this problem? The first constraint tells us that's what y is. Chuck Towle.

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So plus 16 is equal to negative 2. Chuck Towle. And we could see that by actually graphing these lines. Flag Button navigates to signup page. So when we go to the second constraint here, every time we see a y, we say, well, the first constraint tells us that y must be equal to negative 5x plus 8. It's not consistent for 16 to be equal to negative 2. So it looks like this. Posted 2 months ago. This first equation is already in slope y-intercept form. Now we have 10x minus 10x. The Y intercept is at negative six, 24 but we have a negative slope, right? And it's negative 5x plus 8, so 1, 2, 3, 4, 5, 6, 7, 8.